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0=4x^2+380x+6600
We move all terms to the left:
0-(4x^2+380x+6600)=0
We add all the numbers together, and all the variables
-(4x^2+380x+6600)=0
We get rid of parentheses
-4x^2-380x-6600=0
a = -4; b = -380; c = -6600;
Δ = b2-4ac
Δ = -3802-4·(-4)·(-6600)
Δ = 38800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{38800}=\sqrt{400*97}=\sqrt{400}*\sqrt{97}=20\sqrt{97}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-380)-20\sqrt{97}}{2*-4}=\frac{380-20\sqrt{97}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-380)+20\sqrt{97}}{2*-4}=\frac{380+20\sqrt{97}}{-8} $
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